supercuspidal
supercuspidal adjective: that has a zero Jacquet functor for every proper parabolic subgroup.
Adjective
supercuspidal (not comparable)
- That has a zero Jacquet functor for every proper parabolic subgroup
- A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k).2015, Manish Mishra, “A Galois side analogue of a theorem of Bernstein”, in arXiv
Origin of supercuspidal
From super- + cuspidal.
Questions about supercuspidal
- What does supercuspidal mean?
- Supercuspidal means that has a zero Jacquet functor for every proper parabolic subgroup.
- What part of speech is supercuspidal?
- Supercuspidal is an adjective.
Words near supercuspidal in the dictionary
Source and license
Adapted from Wiktionary: supercuspidal (page history and authors). Text available under the Creative Commons Attribution-ShareAlike 4.0 license. Word.ws reformatted the entry and added links. Wiktionary data of 2026-09-02.
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Cite this entry: “supercuspidal.” Word.ws, https://word.ws/supercuspidal. Based on Wiktionary, CC BY-SA 4.0.
